7. A fish tank holds 180 gallons of water and is leaking at a rate of 8 gallons per day. A second fish
sak holds 160 gallons of water and is leaking at a rate of 6 gallons per day. At how many days will
me two fish tanks have the same amount of water?

Respuesta :

Answer:

10 days

Step-by-step explanation:

180 - 8x = 160 - 6x

Solve X (which equals to 10 days)

(x = amount of days)