jimegonza21
jimegonza21
13-11-2019
Chemistry
contestada
the alpha decay of iridium -174
Respuesta :
nkirotedoreen46
nkirotedoreen46
17-11-2019
Answer:
¹⁷⁴₇₇Ir → ¹⁷⁰₇₅Re + ⁴₂He
Explanation:
When a radioisotope undergoes alpha decay its mass number decreases by four while its atomic number decreases by 2.
The mass number of Iridium is 174
Iridium has an atomic number 77
Therefore, the decay equation will be;
¹⁷⁴₇₇Ir → ¹⁷⁰₇₅Re + ⁴₂He
Iridium-174 undergoes alpha decay to form rhenium-170 which has a mass number of 170 and an atomic number 75.
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