Consider this system of linear equations:

22x − y = -23 (equation 1)

11x + 12y = 1 (equation 2)



To find the value of x, you need to substitute x = (y - 23)/22 x = (y + 23)/22 y = 22x + 23 y = 22x - 23 in equation 2.
The value of x is -1 22/23 1 2 .

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If you would like to find the value of x, you can do this using the following steps:

22x - y = -23 ... 22x = y - 23 ... x = (y - 23) / 22
11x + 12y = 1
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11 * (y - 23) / 22 + 12y = 1
(y - 23) / 2 + 12y = 1
y - 23 + 24y = 2
25y = 2 + 23
25y = 25
y = 1

x = (y - 23) / 22 = (1 - 23) / 22 = - 22 / 22 = - 1

The correct result would be: x = -1, y = 1.

Answer:

To find the value of x, you need to substitute y = 22x + 23 in equation 2.

The value of x is -1.

Step-by-step explanation:

22x − y = -23

-y=-22x-23 subtract 22x

y=22x+23 divide both sides by -1

11x+12(22x+23) = 1 substitute y into the second equation

11x+264x+276 = 1 simplify

11x+264x =- 275 subtract 276

275x = -275 simplify

x = -1 divide both sides by 275