kathryngrace321
contestada

Reynaldo drew a rectangular design that was 6 in. wide and 8in. long. He used a copy machine to enlarge the design so that the width was 10 in. What was the length of the enlarged design???

Respuesta :

calculista

Answer:

[tex]13\frac{1}{3}\ in[/tex]

Step-by-step explanation:

we know that

The dilation is a non-rigid transformation that produces similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional and this ratio is called the scale factor

step 1

Find the scale factor

Let

z ----> the scale factor

[tex]z=\frac{10}{6}[/tex] ----> ratio of corresponding sides

simplify

[tex]z=\frac{5}{3}[/tex]

step 2

Find the length of the enlarged design (L)

Multiply the length of the original design by the scale factor

so  

[tex]L=\frac{5}{3}(8)=\frac{40}{3}\ in[/tex]

Convert to mixed number

[tex]\frac{40}{3}\ in=\frac{39}{3}+\frac{1}{3}=13\frac{1}{3}\ in[/tex]

Otras preguntas