Answer:
0.0702J/g°C the specific heat capacity of the metal.
Explanation:m
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})[/tex]
where,
Q = heat absorbed by metal = 186.75 J
[tex]m_1[/tex] = Mass of metal= 19 g
[tex]T_1[/tex] = Initial temperature of metal = [tex]35^oC[/tex]
[tex]T_2[/tex] =Final temperature of metal = [tex]175^oC[/tex]
[tex]c[/tex] = specific heat of metal= ?
[tex]186.75 J=19 g\times c\times (175^oC-35^oC)[/tex]
[tex]c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}[/tex]
[tex]c=0.0702J/g^oC[/tex]
0.0702J/g°C the specific heat capacity of the metal.
