Answer:
[tex]y=4x-14[/tex]
Step-by-step explanation:
Given:
Point (3, -2)
And line equation is [tex]y=4x-3[/tex]
Compare this equation with [tex]y=mx+b[/tex]
The slope of the required line will be m = 4 and point (3. -2)
Find b by plugging the values of m and the point in below equation
[tex]y=mx+b\\[/tex]
Put x and y value from point (3, -2) and slope m value.in above equation.
[tex]-2=4\times 3 +b[/tex]
[tex]-2=12 +b[/tex]
[tex]b=-14[/tex]
So, the equation is passing through the point (3, -2) and parallel to [tex]y=4x-3[/tex] is
[tex]y=mx+b[/tex]
Put [tex]m=4[/tex] and [tex]b = -14[/tex]
[tex]y=4x-14[/tex]
Therefore, equation for the line that passes through (3, -2) and is parallel to the line [tex]y=4x-3[/tex] is
[tex]y=4x-14[/tex]
