Answer:
-7.90
Step-by-step explanation:
Let's write the null hypothesis (H0) and alternative hypothesis (Ha) from the claim statement
P = population proportion of adults who would erase all of their personal information online if they could
H_{0}:P=0.5
H1 P< 0.5
Let's write the given information:
n = sample size = 480
sample proportion = [tex]\hat p = 0.35[/tex]
formula of z test statistic for one sample proportion test is as follows:
[tex]Z=\frac{\hat p-P}{\sqrt{\frac{P\times(1-P)}{n}}}[/tex]
plug the above values in the above formula we get
[tex]Z =\frac{0.35-0.5}{\sqrt{\frac{0.35(1-0.5)}{480}}}=Z=-7.85584[/tex]
So that the test statistic value is -7.90 (Rounded up to two decimal places)
