Answer: d
Explanation:
mass of truck mt, kinetic energy of truck Ekt(Kt), Vt -speed of truck
mass of car ma, kinetic enregy of car Ekc(Kc), Vc-speed of car
mass of truck mt=2*mc
speed of truck Vt=2*Vc
Compare Kinetic energy of truck with kinetic energy of car using equation to calculatation ;
Kinetic energy of car:
Kc=(mc*Vc²)/2
Kinetic energy for truck:
Kt=(mt*Vt²)/2
Kt=((2*mc*(2*Vc)²)/2
Kt=(2*mc*4*Vc²)/2
Kt=8*mc*Vc²/2
Compare Kinteic energy truck with Kinetic energy of car:
Kt/Kc
Kt/Kc=((8*mc*Vc²)/2)/((mc*Vc²)/2)
Kt/Kc=8
The truck has 4 times the KE of the car. Option C is correct. When the truck weighs twice as much as a car, and is moving at twice the speed of the car.
The energy possessed by the body by the virtue of motion is known as the Kinetic energy. It is found as the product of mass and the square of the velocity.
The kinetic energy is found as;
[tex]\rm KE=\frac{1}{2} mv^2[/tex]
Where,
Mass (m)
The velocity is,v
[tex]\rm KE_{car}=\frac{1}{2} mv^2[/tex]
The kinetic energy of the truck is;
[tex]\rm KE_{truck}= \frac{1}{2} (2m)(2v)^2\\\\ KE_{truck}=4 \frac{1}{2} (m)(v)^2\\\\\ KE_{truck}=4 \times KE_{car}[/tex]
Hence, the truck has 4 times the KE of the car. Option C is correct.
#SPJ2
