Answer:
The molecular formula of the compound : [tex]C_4H_{10}N_2[/tex]
Explanation:
The empirical formula of the compound :[tex]C_{2}H_{5}N_{1}[/tex]
To calculate the molecular formula of the compound we will first determine the valency.
The equation used to calculate the valency is :
[tex]n=\frac{\text{molecular mass}}{\text{empirical mass}}[/tex]
We are given:
Mass of molecular formula = 86.16 g/mol
Mass of empirical formula =[tex]12 g/mol\times 2+1 g/mol\times 5+14 g/mol= 43 g/mol[/tex]
Putting values in above equation, we get:
[tex]n=\frac{86.16 g/mol}{43 g/mol}=2[/tex]
The molecular formula of the compound :
[tex]C_{2n}H_{5n}N_{1n}=C_{2\times 2}H_{5\times 2}N_{1\times 2}[/tex]
= [tex]C_4H_{10}N_2[/tex]
