33.2 g of iron (Fe)
Explanation:
We have the following chemical reaction in which iron react with oxygen to form the iron (III) oxide:
4 Fe + 3 O₂ → 2 Fe₂O₃
number of moles = volume / 22.4 (L/mole)
number of moles of O₂ = 10 / 22.4
number of moles of O₂ = 0.446 moles
Taking in account the chemical reaction we devise the following reasoning:
if 4 moles of Fe react with 3 moles of O₂
then X moles of Fe react with 0.446 moles of O₂
X = (4 × 0.446) / 3 = 0.595 moles of Fe
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe = 0.595 × 55.8
mass of Fe = 33.2 g
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