Answer:
3/8
Step-by-step explanation:
total number in bit string of lent 4=16
let s be the set of all bit strings of length 4
the probability tat an event is randomly selected is A
that an event is randomly selected and has two strings of 0s B
number of strings with 1 to s=8
probability of selecting A
P(A)=8/16=1/2
strings in S starting with S and having two consecutive zeros are 1000,1001
P(AnB)=3/16
the conditional probability that a randomly generated bit string of length four contains at least two consecutive 0s
P(AnB)/P(A)=3/16/1/2
3/8