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A permanent magnet DC motor has an armature resistance of 0.5 Ω and when a voltage of 120 V is applied to the motor it reaches a steady‐state speed of rotation of 20rev/s and draws 40A. What will be:

(a) the power input to the motor?
(b) the power loss in the armature?
(c) the torque generated at that speed?

Respuesta :

NBAyoungboyglz23

Answer:

12 N-m

Explanation:

The dc motor is operating at 24 V that is its terminal voltage V =24 V

Armature resistance  = 0.2 ohm

No load speed = 240 radian /sec

For motor we know that  as the motor is on no load so  so

Power developed in the motor

Now we know that power = torque× angular speed

So

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