Answer:
It will take Joanna nearly the same time as Karen to run the park and time taken is 15 min and 7 seconds.
Step-by-step explanation:
Let the time taken by Joanne be 'x' minutes.
Given:
Total distance traveled by both is, [tex]d=5000\ ft[/tex]
Speed of Karen is 2.5 feet per minute slower than Joanne's.
Time taken by Karen is, [tex]T_K=15\ min[/tex]
Now, speed of Karen is given as:
[tex]S_K=\frac{Distance}{Time}\\S_K=\frac{d}{T_K}\\S_K=\frac{5000}{15}=\frac{1000}{3}\ ft/min[/tex]
Now, as per question,
Speed of Karen = Speed of Joanne - 2.5
∴ Speed of Joanne = Speed of Karen + 2.5
[tex]S_J=\frac{1000}{3}-2.5\\\\S_J=\frac{1985}{6}\ ft/min[/tex]
Now, we have speed of Joanne and distance traveled by Joanne. Therefore, time taken by Joanne is given as:
[tex]x=\frac{Distance}{Speed}\\\\x=\frac{d}{S_J}\\\\x=5000\div \frac{1985}{6}\\\\x=5000\times \frac{6}{1985}\\\\x=\frac{5000\times 6}{1985}=15.11\ min\approx15\ min 7\ seconds[/tex]
Therefore, it will take Joanna nearly the same time to run the park and time taken is 15 min and 7 seconds.