Answer:
0.0735,0.0179,0.7026
Step-by-step explanation:
Given that a simple random sample of size nequals 49 is obtained from a population with mu equals 78 and sigma equals 28.
Sample size = 49
Population mean = 78
Population std deviation = 28
Std error of sample mean = [tex]\frac{\sigma}{\sqrt{n} } \\=4[/tex]
a) [tex]\bar x[/tex]: N(78, 4)
b) [tex]P(\bar x >83.8)\\=0.0735[/tex]
(by converting to Z and finding value from Z table)
c) P (x overbar less than or equals 69.6 )
=[tex]P(\bar x \leq 69.6)\\=0.0179[/tex]
d) P (75.8 less than x overbar less than 88 )
=[tex]P(75.8<X<88)\\= 0.9938-0.2912\\=0.7026[/tex]
