Answer:
The Work Done is [tex]3 \times 10^5 \ J.[/tex]
Explanation:
Since , the equipment is pulled in horizontal horizontal plane.
Therefore, its normal reaction must be equal to its weight.
So, Normal reaction, [tex]N=6000\ N.[/tex]
We know, frictional force , [tex]F=\mu\times N.[/tex]
(Where N is Normal reaction and [tex]\mu[/tex] is coefficient of kinetic friction )
Therefore, [tex]F=0.05 \times 6000\ N=300 \ N.[/tex]
We know ,
[tex]Work Done , W=F\times D[/tex]
( Here D is distance covered by the force)
Putting, D=1000 m.
We get , Work Done[tex]=300\times 1000 \ J\\=3\times 10^5 \ J.[/tex]
