According to a survey published by ComPsych Corporation, 54% of all workers read e-mail while they are talking on the phone. Suppose that 20% of those who read e-mail while they are talking on the phone write personal "to-do" lists during meetings. Assuming that these figures are true for all workers, if a worker is randomly selected, determine the following probabilities:

a. The worker does not write personal "to-do" lists given that he reads e-mail while talking on the phone.
b. The worker does not write personal "to-do" lists given that he reads e-mail while talking on the phone.
c. The worker does not write personal "to-do" lists and does read e-mail while talking on the phone.

Question

sparksy1353 sparksy1353

13-12-2019
Mathematics

contestada

According to a survey published by ComPsych Corporation, 54% of all workers read e-mail while they are talking on the phone. Suppose that 20% of those who read e-mail while they are talking on the phone write personal "to-do" lists during meetings. Assuming that these figures are true for all workers, if a worker is randomly selected, determine the following probabilities:

a. The worker does not write personal "to-do" lists given that he reads e-mail while talking on the phone.
b. The worker does not write personal "to-do" lists given that he reads e-mail while talking on the phone.
c. The worker does not write personal "to-do" lists and does read e-mail while talking on the phone.

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mtosi17 mtosi17 · Answer 1 · 2019-12-15T06:30:58+01:00

Answer:

The probability of the worker does not write personal "to-do" lists given that he reads e-mail while talking on the phone is P=0.8.

Step-by-step explanation:

a) The worker does not write personal "to-do" lists ([tex]\bar W[/tex]) given that he reads e-mail while talking on the phone ([tex]R[/tex]):

[tex]P(\bar W|R)=1-P(W|R)=1-0.2=0.8[/tex]

If it is given that he reads e-mail, we pick out of the 54% of the workers. In this group of workers, 20% write to-do list, so it means that 80% doesn't write to-do lists.