A 7 kg cart is moving down a track at a speed of 9 m/s and hits a 11 kg cart sitting still. The two have an inelastic collision. What is the resulting speed after the collision?

Respuesta :

Answer: 3.5 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle which establishes the initial momentum [tex]p_{i}[/tex] must be equal to the final momentum [tex]p_{f}[/tex], and taking into account this is an inelastic collision:

Before the collision:

[tex]p_{i}=mV_{o}+MU_{o}[/tex] (1)

After the collision:

[tex]p_{f}=(m+M)V_{f}[/tex] (2)

Where:

[tex]m=7 kg[/tex] is the mass of the first cart

[tex]V_{o}=9 m/s[/tex] is the velocity of the first cart

[tex]M=11 kg[/tex] is the mass of the second cart

[tex]U_{o}=0 m/s[/tex] is the velocity of the second cart

[tex]V_{f}[/tex] is the final velocity of both carts

[tex]p_{i}=p_{f}[/tex] (3)

[tex]mV_{o}+MU_{o}=(m+M)V_{f}[/tex] (4)

Since [tex]U_{o}=0 m/s[/tex]:

[tex]mV_{o}=(m+M)V_{f}[/tex] (5)

[tex]V_{f}=\frac{mV_{o}}{m+M}[/tex] (6)

[tex]V_{f}=\frac{(7 kg)(9 m/s)}{7 kg + 11 kg}[/tex] (7)

Finally:

[tex]V_{f}=3.5 m/s[/tex]