Answer:
The surface area of the paperweight is [tex]SA=8.3\ in^2[/tex]
Step-by-step explanation:
we know that
The surface area of the triangular prism is equal to the area of its triangular base plus the area of its three triangular lateral faces
so
Find the area of its triangular base
[tex]SA=\frac{1}{2}(2)(1.7)[/tex]
[tex]SA=1.7\ in^2[/tex]
Find the area of its three triangular lateral faces
[tex]SA=3[\frac{1}{2}(2)(2.2)][/tex]
[tex]SA=6.6\ in^2[/tex]
Adds the areas
[tex]SA=1.7+6.6[/tex]
[tex]SA=8.3\ in^2[/tex]
