contestada

Formula
13.
Find the number of real number solutions for the equation.
y2 + 26 = 0
odratic
100%
0
ant and
0
scriminant
g Data
90%
0
ssions and

Respuesta :

Answer:

Step-by-step explanation:

y²+26=0

disc=0-4*26=-104<0

no real solution.

Answer:

There are no real solutions.

Step-by-step explanation:

The equation given is:

[tex]y^{2}+26=0[/tex]

[tex]y^{2}=-26[/tex]

LHS of the equation is always a positive quantity as square of any number is always positive.But RHS is a negative number.This is not possible.

Hence there are no real solutions.

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