The cost of one chicken is $8 and cost of one duck is $5.
Step-by-step explanation:
Let,
Cost of one chicken = x
Cost of one duck = y
According to given statement;
50x+30y=550 Eqn 1
44x+36y=532 Eqn 2
Multiplying Eqn 1 by 36
[tex]36(50x+30y=550)\\1800x+1080y=19800\ \ \ Eqn\ 3[/tex]
Multiplying Eqn 2 by 30
[tex]30(44x+36y=532)\\1320x+1080y=15960\ \ \ Eqn\ 4[/tex]
Subtracting Eqn 4 from Eqn 3
[tex](1800x+1080y)-(1320x+1080y)=19800-15960\\1800x+1080y-1320x-1080y=3840\\480x=3840[/tex]
Dividing both sides by 480
[tex]\frac{480x}{480}=\frac{3840}{480}\\x=8[/tex]
Putting x=8 in Eqn 1;
[tex]50(8)+30y=550\\400+30y=550\\30y=550-400\\30y=150[/tex]
Dividing both sides by 30
[tex]\frac{30y}{30}=\frac{150}{30}\\y=5[/tex]
The cost of one chicken is $8 and cost of one duck is $5.
Keywords: linear equation, elimination method
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