Respuesta :
Answer:
Option B) (-2,1) is correct.
Step-by-step explanation:
The given equations are, [tex]y=1/2x+ 2 and y = -2x - 3[/tex].
Let the point of intersection be (a,b).
Thus (a,b) satisfies both the equations.
[tex]b=1/2a+ 2[/tex]
[tex]b = -2a - 3[/tex]
subtracting both the equations we get,
[tex](\frac{5}{2})(x) = -5[/tex]
x = -2, now inserting this value in anyone of the equations,
[tex]y = -2(-2) -3 = 4-3 = 1[/tex]
Thus, the intersection point is (-2,1).
Answer: B. (-2,1)
Step-by-step explanation:
Hi, to answer this question we have to solve the system of equations:
y=1/2x+ 2
y = -2x - 3
Multiplying the first equation by 4 and adding both equations:
4y = 2x +8
+
y = -2x - 3
---------------
5y = 5
y =5/5
y=1
Replacing the value of y in any equation:
y = -2x - 3
1 = -2x - 3
Solving for x:
2x =-3-1
2x=-4
x =-4/2
x =-2
So, the solution is
x =-2; y = 1
The correct option is B. (-2,1)