Respuesta :
Answer:
area will be four times the first area
Step-by-step explanation:
the diameter of the first sphere=d
therefore radius=d/2
=r
the diameter of the second sphere becomes 2d
therefore the radius of second sphere=2r
area of a sphere=4×pi×r^2
the ratio of the two spheres=(4pi(2r)^2)/(4pir^2)
=(4pi4r^2)/4pir^2
cancelling 4pir^2, you get 4:1
therefore the area of the second sphere is 4 times the first one
Surface area of a sphere: S=4pi%2Ar%5E2
Remember, the diameter is d=2r. So if the diameter is doubled, then the new radius is 2r units (instead of "r" units)
S=4pi%2Ar%5E2 Start with the given equation.
S=4pi%2A%282r%29%5E2 Replace the original "r" with "2r".
S=4pi%2A4r%5E2 Square 2r to get 4r%5E2
So the old equation is S%5Bold%5D=4pi%2Ar%5E2 and the new one is S%5Bnew%5D=4pi%2A4r%5E2
The ratio of the new surface area to the old surface area is then:
S%5Bnew%5D%2FS%5Bold%5D=%284pi%2A4r%5E2%29%2F%284pi%2Ar%5E2%29
Highlight the common terms
Cancel out the common terms
S%5Bnew%5D%2FS%5Bold%5D=4 Simplify
Remember, the diameter is d=2r. So if the diameter is doubled, then the new radius is 2r units (instead of "r" units)
S=4pi%2Ar%5E2 Start with the given equation.
S=4pi%2A%282r%29%5E2 Replace the original "r" with "2r".
S=4pi%2A4r%5E2 Square 2r to get 4r%5E2
So the old equation is S%5Bold%5D=4pi%2Ar%5E2 and the new one is S%5Bnew%5D=4pi%2A4r%5E2
The ratio of the new surface area to the old surface area is then:
S%5Bnew%5D%2FS%5Bold%5D=%284pi%2A4r%5E2%29%2F%284pi%2Ar%5E2%29
Highlight the common terms
Cancel out the common terms
S%5Bnew%5D%2FS%5Bold%5D=4 Simplify