Answer:
d. When aluminum-28 undergoes beta decay, silicon-28 is produced.
Step-by-step explanation:
so, option a is wrong.
so,option b is wrong.
beta decay reaction for aluminum-28 is :
[tex]Al_{13}28 -> Si_{14}28 + \beta _{-1} 0[/tex]
[where, [tex]A_{c}b[/tex] represents, element A,
b: its mass number[=number of protons+number of neutrons in the element]
, c : atomic number[=number of protons in the element]
so, option c is wrong and option d is correct.