The mid-point of (1,5) and (-4,-5) is [tex](-\frac{3}{2}, 0)[/tex]
Step-by-step explanation:
The mid-point is calculated using the coordinates of the given points
The formula for mid-point M is given by:
[tex]M(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\[/tex]
Given
(x1,y1) = (1,5)
(x2,y2) = (-4,-5)
[tex]So\\M(x,y) = (\frac{1-4}{2}, \frac{5-5}{2})\\=(\frac{-3}{2} , \frac{0}{2}\\=(-\frac{3}{2}, 0)[/tex]
Hence,
The mid-point of (1,5) and (-4,-5) is [tex](-\frac{3}{2}, 0)[/tex]
Keywords: Mid-point, coordinate geometry
Learn more about coordinate geometry at:
- brainly.com/question/12685482
- brainly.com/question/12639288
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