The angle of depression from the basketball hoop to Clairs eyes is 9.2degrees. The vertical distance from the ground to Claires eyes is 5.6 feet. Using the diagram, find the height of the basketball hoop to the nearest tenth.
x - difference between the height of the basketball hoop and the vertical distance from the ground to Clair´s eyes. Using T O A: tan (9.2°) = x / 22 ft x = tan (9.2°) · 22 ft x = 0.162 · 22 ft x = 3.564 ft The height of the basketball hoop is: h = 5.6 + 3.564 = 9.164 feet
