aydenjcarpenter
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What is the molarity of a 2.4-liter solution containing 124 grams of HF?

a. 2.6 M HF <----- my guess based on calculations
b. 6.2 M HF
c. 8.3 M HF
d. 15 M HF

Respuesta :

Willchemistry
Molar mass:

HF = 1 + 19 = 20.0 g/mol

Number of moles :

124 / 20.0 =>  6.2 moles

Volume = 2.4 L

M = n / V

M = 6.2 / 2.4

M = 2.6 M

Answer A

hope this helps!

JoshEast
The Answer is A as you said:

Molarity = [tex] \frac{no. of moles}{volume} [/tex]

moles of HF = [tex] \frac{mass}{molar mass} [/tex]
                    = [tex] \frac{124}{(1 + 19)} [/tex]
                    = 6.2 mol

∴  molarity of HF = [tex] \frac{6.2 mol}{2.4 dm^{3} } [/tex]
                           = 2.58 M
                           ≈ 2.6 M

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