Respuesta :
I see what's going on, we have to find the number of students in the intersection. Math is 120, Science is 50, neither is 100. Add all of these together, 120 + 50 + 100 = 270, then subtract from 300, 300-270 = 30
Now, we divide 30/300 which gives .1, move the decimal over 2 places to the right and that makes it 10%
Now, we divide 30/300 which gives .1, move the decimal over 2 places to the right and that makes it 10%
Answer: [tex]\frac{1}{10}[/tex]
Step-by-step explanation:
Since, The total number of student = 300
Out of which,
The number of students who are only in Maths = 120
And, The number of students who are only in Science = 50
While, the students who are not from any subject = 100
Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None
= 300 - 120 - 50 - 100
= 30
That is, there are 30 students who are both from science and maths,
Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10