Answer:
Highest energy will be equal to [tex]9.6\times 10^{-13}J[/tex]
Explanation:
Charged on doubly ionized helium atom [tex]q=2e=2\times 1.6\times 10^{-19}C=3.2\times 10^{-19}C[/tex]
It is accelerated with maximum voltage of 3 MV
So voltage [tex]V=3\times 10^6volt[/tex]
Now energy is given by [tex]E=qV=3.2\times 10^{-19}\times 3\times 10^6=9.6\times 10^{-13}J[/tex]
So highest energy will be equal to [tex]9.6\times 10^{-13}J[/tex]
