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You dilute 225 mL of a 4.5 M calcium carbonate solution. You need a final concentration of 0.038 M calcium carbonate. What volume of solution can be made at this concentration from the original solution

Respuesta :

Answer:

The total volum should be 26.64 L, this means we have to add 26.415 L

Explanation:

Step 1: Data given

Volume = 225 mL = 0.225 L

Molarity = 4.5 M

We dilute to a final concentration of 0.038 M

Step 2: Calculate the volume

C1V1 = C2V2

⇒ with C1 = the initial concentration = 4.5 M

⇒ with V1 = the initial volume = 0.225 L

⇒ with C2 = the final concentration = 0.038 M

⇒ with V2 = the final volume = TO BE DETERMINED

4.5M * 0.225L = 0.038M * V2

V2 = 26.64 L

The total volum should be 26.64 L, this means we have to add 26.415 L

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