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What is the net ionic equation for the reaction of solid iron with aqueous copper sulfate? (Hint: First use the activity series to write the formula unit equation!) 1. 2 Fe(s) + 3 CuSO4(aq) → Fe2(SO4)3(s) + 3 Cu(s) 2. 2 Fe(s) + 3 Cu2+(aq) + 3 SO2− 4 (aq) → Fe2(SO4)3(s) + 3 Cu(s) 3. No reaction occurs. 4. 2 Fe(s) + 3 CuSO4(aq) → Fe2(SO4)3(aq) + 3 Cu(s) 5. 2 Fe(s) + 3 Cu2+(aq) + 3 SO2− 4 (aq) → 2 Fe3+(aq) + 3 SO2− 4 (aq) + 3 Cu(s) 6. 2 Fe(s) + 3 Cu2+(aq) → 2 Fe3+(aq) + 3 Cu(s)

Respuesta :

Answer:

6. 2 Fe(s) + 3 Cu2+(aq) → 2 Fe3+(aq) + 3 Cu(s).

Explanation:

The reaction of solid iron with aqueous copper sulfate is an example of a single displacement type of reaction.

Half equations

2 Fe(s) → 2Fe2+(aq)

3CuSO4(aq) → 3Cu(s) + 3SO4^2-(aq)

Net ionic equation:

2Fe(s) + 3Cu2+(aq) → Fe2+(s) + 3Cu(aq)

2Fe(s) + 3CuSO4(aq) → Fe2(SO4)3(s) + 3Cu2+(aq)

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