Respuesta :
Answer:
[tex]f'(x) + 3[/tex]
Step-by-step explanation:
A slow freight train chugs along a straight track. The distance it has traveled after x hours is given by a function f(x)
The speed of the train is the derivative of the distance traveled f(x)
The speed of the train is f'(x)
An engineer is walking along the top of the box cars at the rate of 3 mi/hr in the same direction as the train is moving.
3 mi/hr is the speed relative to the train
he speed of the engineer is the speed of the train plus the rate in same direction
[tex]f'(x) + 3[/tex]
You can use the fact that the net speed of engineer will be addition of his speed relative to train and train's speed relative to ground.
The formula for the speed of engineer relative to the ground in terms of x and f is given by
[tex]f'(x) + 3[/tex] miles per hour.
How to get the speed of engineer relative to the ground?
Since the speed of the train relative to ground is rate of the distance function, thus
speed of train relative to ground= f'(x)
Since the speed of the engineer with respect to train(in train's travelling direction) = 3 miles/hour
thus,
Net speed of engineer with respect to ground = [tex]f'(x) + 3[/tex] miles per hour.
Thus,
The formula for the speed of engineer relative to the ground in terms of x and f is given by
[tex]f'(x) + 3[/tex] miles per hour.
Learn more about relative speed here:
https://brainly.com/question/14641310
