Respuesta :
Answer:
9.21 ppm
Explanation:
Considering
[tex]concentration_{working\ solution}\times Volume_{working\ solution}=concentration_{stock\ solution}\times Volume_{stock\ solution}[/tex]
Given that:
[tex]concentration_{working\ solution}=?[/tex]
[tex]Volume_{working\ solution}=25.00mL[/tex]
[tex]Volume_{stock\ solution}=4.60mL[/tex]
[tex]concentration_{stock\ solution}=50.04 ppm[/tex]
So,
[tex]concentration_{working\ solution}\times 25.00mL=50.04 ppm\times 4.60mL[/tex]
[tex]concentration_{working\ solution}=\frac{50.04\times 4.60}{25.00}\ ppm=9.21\ ppm[/tex]
The concentration of standard dilution will be 3.68ppm.
Given:
Conc. of standard stock solution, M₁ = 50.04ppm
Volume of standard stock solution, V₁ = 4.60mL
Volume of flask, V₂ = 25.00 mL
To find:
Conc. of the standard dilution, M₂ = ?
Dilution:
- The concentration or volume of the concentrated or dilute solution using the equation: [tex]M_1V_1 = M_2V_2[/tex]
- This law based on the conservation of moles.
Now, substituting the values in the above formula.
[tex]M_1V_1=M_2V_2\\\\50.04*4.60=M_2*25.00\\\\M_2=\frac{50.04*4.60}{25.00} \\\\M_2=3.68ppm[/tex]
Thus, the concentration of standard dilution will be 3.68ppm.
Find more information about "Dilution" here:
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