You are working on charge-storage devices for a research center. Your goal is to store as much charge on a given device as possible. The facilities allow you to generate almost any potential difference V you need, but you are restricted to using a single parallel-plate capacitor. The area and separation distance of the plates are fixed, and the dielectric materials available to you are paper (κ = 3.0, Emax=4.0×107V/m), Mylar (κ = 3.3, Emax=4.3×108V/m), quartz (κ = 4.3, Emax=8×106V/m), and mica (κ = 5, Emax=2×108V/m).
Part A. What properties of these materials must you consider in choosing the best dielectric for your needs? Check all that apply.
a. mass density
b. dielectric constant breakdown threshold
c. electric conductivity
Part B. Rank the materials in order of their ability to meet your needs, first choice first. Rank the materials from the most appropriate to the least appropriate. To rank items as equivalent, overlap them. HelpReset paperquartzmicaMylar Least appropriateMost appropriate The correct ranking cannot be determined.

Where the dielectric constant (ε) is the value of the material between the plates of the capacitor, we see that as if value increases the capacity also increases.

Another magnitude that we must take into account that the maximum working voltage, the greater the safer is the capacitor

the flexibility of the material must also be taken into account

Part A the answer is the dielectric constant.

Pate B order the materials from best to worst

Mica. The best ever

Mylar Flexible

Paper Low capacity, low working voltage, flexible

Quartz high dielectric, but brittle

pristina pristina · Answer 2 · 2022-02-17T15:35:21+01:00

Part A: Dielectric constant and breakdown voltage of the material must be considered for choosing the best dielectric.

Part B: Mica is the most appropriate material and paper is the least appropriate.

Parallel Plate Capacitor

Part A:

The charge stored in a capacitor is given by;

[tex]Q=CV[/tex]

The capacitance of a parallel plate capacitor with a dielectric in the middle is given by;

[tex]C = \kappa\frac{\epsilon_0 A}{d}[/tex]

Where, [tex]\kappa[/tex] is the dielectric constant of the material.

If the value of the dielectric constant increases, the capacitance also increases.

Also, as the voltage increases the amount of charge stored will also increase.

So, the breakdown voltage that the material can tolerate has to be large in case of a good dielectric.

Part B:

Mica is the most appropriate material.

Quartz is the second-best choice.

Mylar is the next best choice.

Paper is the least appropriate material.

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