contestada

alpha decay is a nuclear decay in which a helium nucleus is emitted. If the helium nucleus has a mass of 6.8*10^-27 kg and is given 5.8 MeV of kinetic energy what is its velocity

Respuesta :

boffeemadrid

Answer:

16520931.465 m/s

Explanation:

K = Kinetic energy = 5.8 MeV

m = Mass of nucleus = [tex]6.8\times 10^{-27}\ kg[/tex]

Speed of a particle is given by

[tex]v=\sqrt{\dfrac{2K}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 5.8\times 10^6\times 1.6\times 10^{-19}}{6.8\times 10^{-27}}}\\\Rightarrow v=16520931.465\ m/s[/tex]

The velocity is 16520931.465 m/s