(15 POINTS) For the following system, use the second equation to make a substitution for y in the first equation.

2x + y = 5
y + 3 = 2x

a) 2 x + 3 - 2 x = 5
b) 2 x + 2 x - 3 = 5
c) 2 x + 2 x + 3 = 5

To solve for Y in the second equation, (which will allow you to use it to substitute) you must get Y by itself. To do this, you must add three, which makes the equation, Y = 2x - 3. Which you've now solved your second equation, now you can plug it in / substitute it for the Y in the first equation. It should look like this: 2x +2x-3 since that is what Y equals according to the other equation.

If you're still confused by this, I am happy to tell you more in detail, otherwise, here's your answer! :D

(15 POINTS) For the following system, use the second equation to make a substitution for y in the first equation. 2x + y = 5 y + 3 = 2x a) 2 x + 3 - 2 x = 5 b) 2 x + 2 x - 3 = 5 c) 2 x + 2 x + 3 = 5

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(15 POINTS) For the following system, use the second equation to make a substitution for y in the first equation.

2x + y = 5
y + 3 = 2x

a) 2 x + 3 - 2 x = 5
b) 2 x + 2 x - 3 = 5
c) 2 x + 2 x + 3 = 5