Answer:
c = [tex]\frac{b^2-R^2}{4a}[/tex]
Step-by-step explanation:
Given
R= [tex]\sqrt{b^2-4ac}[/tex]
Clear the radical by squaring both sides
R² = b² - 4ac ( subtract b² from both sides )
R² - b² = - 4ac ( multiply all terms by - 1 )
b² - R² = 4ac ( divide both sides by 4a )
[tex]\frac{b^2-R^2}{4a}[/tex] = c
Answer:
c=[tex]\frac{b^2-R^2}{4a}[/tex]
Step-by-step explanation:
First, get rid of the square root by squaring both sides:[tex]R^{2}[/tex]=[tex]b^{2}[/tex]-4ac
Next, add 4ac to both sides: 4ac+[tex]R^{2}[/tex]=[tex]b^{2}[/tex]
Then, subtract [tex]R^{2}[/tex] from both sides: 4ac=[tex]b^{2}[/tex]-[tex]R^{2}[/tex]
Finally, divide both sides by 4a to get your answer: c=[tex]\frac{b^2-R^2}{4a}[/tex]
