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You are climbing in the High Sierra where you suddenly find yourself at the edge of a fog-shrouded cliff. To find the height of this cliff, you drop a rock from the top and 9.30s later hear the sound of it hitting the ground at the foot of the cliff.

Part A
Ignoring air resistance, how high is the cliff if the speed of sound is 330 m/s?
Express your answer with the appropriate units.
h =__________
Part B
Suppose you had ignored the time it takes the sound to reach you. In that case, would you have overestimated or underestimated the height of the cliff?

Respuesta :

Explanation:

Using,

S = vi*t + 1/2*a*tr^2

vi = initial velocity = 0 m/s

S = 1/2 * 9.8 * tr^2

= 4.9tr^2.

S = vf * (ta - tr)

4.9tr^2 = 330 * (9.3 - tr)

4.9tr^2 - 3069 + 300 * tr)

Using general quadratic equation,

tr = 8.93 s.

S = 4.9 * (8.93)

= 390.75 m.

B.

Therefore,

S = 4.9 * (9.3)^2

= 423.8 m.

The height of the cliff would be overestimated.

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