Respuesta :
Answer:
a)
10.25
19.69
12.61
22.05
24.41
b)
P ( 14.97 < x < 19.69 ) = 0.68
c)
P ( 12.61 < x < 22.05 ) = 0.95
Step-by-step explanation:
Given:
- Sample mean x_bar = 17.33
- Sample mean s.d = 2.36
Find:
x_bar - 3s
x_bar + s
x_bar - 2s
x_bar + 2s
x_bar + 3s
Apply Property 1 of the empirical rule to make pertinent statements about the observations in the sample At least 8 out of 70 fifth-grade classes sampled have student-to-faculty ratios between 15.36 and 17.86
Apply Property 2 of the empirical rule to make pertinent statements about the observations in the sample. At least out of 70 fifth-grade classes sampled have student-to-faculty ratios between and Type integers or decimals.
Solution:
part a)
x_bar - 3s = 17.33 - 3*2.36 = 10.25
x_bar - 2s = 17.33 - 2*2.36 = 12.61
x_bar - s = 17.33 - 2.36 = 14.97
x_bar + 3s = 17.33 + 3*2.36 = 24.41
x_bar + 2s = 17.33 + 2*2.36 = 22.05
x_bar + s = 17.33 + 2.36 = 19.69
part b)
- The first property of empirical rule states that the probability of score between 1 standard deviation from the mean is 68 %. Hence,
P ( x_bar - s.d < x < x_bar + s.d ) = 0.68
P ( 14.97 < x < 19.69 ) = 0.68
part c)
- The first property of empirical rule states that the probability of score between 2 standard deviation from the mean is 95 %. Hence,
P ( x_bar - 2*s.d < x < x_bar + 2*s.d ) = 0.95
P ( 12.61 < x < 22.05 ) = 0.95