Answer:
a) Radius of electron' s orbit = 5.29 × 10⁻¹¹ m
b) Centripetal Acceleration, α = 9.15 × 10²² m/s²
Explanation:
The force of attraction between a proton and an electron of the simple model of Hydrogen atom is obtained from literature to be 8.325 × 10⁻⁸ N
It is this force that is driving the the circular motion of the electron. Centripetal force is given by
F = mv²/r
r = mv²/F
m = mass of the electron = 9.11 × 10⁻³¹ kg
v = velocity of the electron = 2.2 × 10⁶ m/s
r = 9.11 × 10⁻³¹ × (2.2 × 10⁶)²/(8.325 × 10⁻⁸)
r = 5.29 × 10⁻¹¹ m
b) centripetal acceleration, α = F/m or v²/r
α = (8.325 × 10⁻⁸)/(9.11 × 10⁻³¹) = (2.2 × 10⁶)²/(5.29 × 10⁻¹¹) = 9.15 × 10²² m/s²
