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You hang a heavy ball with a mass of 94 kg from a platinum rod 3.2 m long by 2.2 mm by 3.1 mm. You measure the stretch of the rod, and find that the rod stretched 0.002588 m. Part 1 (a) Using these experimental data, what value of Young's modulus do you get? Y= N/m2 the tolerance is +/-2% By accessing this Question Assistance, you will learn while you earn points based on the Point Potential Policy set by your instructor.

Respuesta :

Answer:

[tex]1.67\times 10^{11} N/m^2[/tex]

Explanation:

Mass of the ball, [tex]m=94 kg[/tex]

Force = weight of the ball

[tex]F=mg = 94kg\times 9.81 m/s^2=922.14N[/tex]

For Young's modulus, substitute the values in the formula which is as follows:

[tex]\frac{F}{A}=Y\frac{\Delta L}{L}\\\Rightarrow Y= \frac{FL}{A\Delta L}\\\Rightarrow Y =\frac{922.14 \times 3.2}{2.2\times 10^{-3}\times 3.1\times 10^{-3} \times 0.002588}=1.67\times 10^{11} N/m^2[/tex]

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