Respuesta :
Answer:
Solution with electrolyte will have a lower freezing point than the solution with non electrolyte.
Explanation:
Depression in freezing point is given by :
[tex]\Delta T_f=i\times k_f\times m[/tex]
Where :
i = van't Hoff factor
[tex]k_f[/tex] = Molal depression constant of solvent
m = molaity of the solution
Let the molality of the glucose and NaCl solution be = m
Molal depression constant of water = [tex]k_f[/tex]
1) The values of van't Hoff factor for glucose is = 1 (non electrolyte)
Depression in freezing point of glucose solution :
[tex]\Delta T_f=1\times k_b\time m[/tex]
2) The values of van't Hoff factor for NaCl is = 2 (electrolyte)
[tex]NaCl\rightarrow Na^++Cl^-[/tex]
Depression in freezing point of NaCl solution :
[tex]\Delta T_f'=2\times k_b\time m[/tex]
[tex]\Delta T_f<\Delta T_f'[/tex]
[tex]1\times k_b\time m<2\times k_b\time m[/tex]
1 < 2
Higher the depression in freezing point more will be the lower freezing point of the solution.This means that solution with electrolyte will have a lower freezing point than the solution with non electrolyte.
