Answer: a) 29.25 ∘C b) 7.66 cm
Explanation:
a) We need to find the temperature at the fat-inner fur boundary so bear loses heat at rate of 50.8
Rate of heat is related to temperature as:
Rate= Thermal conductivity of fat * Area * Change in temperature / Fat layer length
So,
50.8= 0.2 * [tex]4\pi *(\frac{1.4}{2} )^{2}[/tex] * ( 30.9 + 273 - T ) / 0.040
T= 302.25 K
T= 29.25 ∘C
b)
We have
Thermal conductivity of air= 0.024 W/(m⋅K)
Rate= Thermal conductivity of air * Area * Change in temperature / Air layer length
50.8= 0.024 * [tex]4\pi *(\frac{1.4}{2} )^{2}[/tex] * ( 29.25- 2.9 ) / L
L= 0.076 m
L= 7.66 cm