Answer: Concentration of [tex]Ca(OH)_2[/tex] is [tex]5.9\times 10{-4}M[/tex]
Explanation:
pH or pOH is the measure of acidity or alkalinity of a solution.
pH is calculated by taking negative logarithm of hydrogen ion concentration.
[tex]pH=-\log [H^+][/tex]
[tex]pOH=-\log [OH^-][/tex]
[tex]12.11+pOH=14[/tex]
[tex]pOH=1.89[/tex]
[tex]1.89=-\log [OH^-][/tex]
[tex][OH^-]=0.0129[/tex]
[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^{-}[/tex]
According to stoichiometry,
2 mole of [tex]OH^-[/tex] are produced by = 1 mole of [tex]Ca(OH)_2[/tex]
Thus 0.0129 moles of [tex]OH^-[/tex] are produced by =[tex]\frac{1}{2}\times 0.0129=5.86\times 10{-4}[/tex] moles of [tex]Ca(OH)_2[/tex]
The concentration of [tex]Ca(OH)_2[/tex] is [tex]5.9\times 10{-4}M[/tex]
