contestada

In this problem, the tapes used were assumed to be 30.0 m long. Later, when the tapes were standardized, they were found to have different tape lengths. Determine the correct distance measured if the measured distance was 1858.23 m, and the correct tape length was 29.97 m. Use two decimal places

Respuesta :

adelekeademolu

Answer:

1856.37 m

Step-by-step explanation:

When the tapes were taken as 30.0 m long, the measured distance was 1858.23 m. This is equivalent to [tex]\dfrac{1858.23}{30}=61.941[/tex] tapes.

With the correct tape length now 29.97 m, the measured distance is

[tex]29.97\times61.941 \text{ m} = 1856.37177 \text{ m} = 1856.37 \text{ m} [/tex] to 2 decimal places.

Otras preguntas