Respuesta :
Note: As you may have unintentionally missed to add the diagram. After a little research, I was able to find the diagram. I have attached the diagram, based on which I am solving which anyways would clear your concepts.
Answer:
The area of the storage facility is [tex]20x^2-4x-16\:\:square\:feet[/tex].
Step-by-step explanation:
From the attached diagram, it is clear that
- The length of the rectangle [tex]=5x + 4[/tex]
- The width of the rectangle [tex]= 4x - 4[/tex]
The area of the storage facility in square feet can be calculated by finding the area of rectangle.
So, using the area of rectangle formula
[tex]A = lw[/tex]
[tex]=\:\left(5x+4\right)\left(4x-4\right)[/tex]
[tex]\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd[/tex]
[tex]a=5x,\:b=4,\:c=4x,\:d=-4[/tex]
[tex]=5x\cdot \:4x+5x\left(-4\right)+4\cdot \:4x+4\left(-4\right)[/tex]
[tex]=5\cdot \:4xx-5\cdot \:4x+4\cdot \:4x-4\cdot \:4[/tex]
[tex]=20x^2-4x-16[/tex]
Therefore, the area of the storage facility is [tex]20x^2-4x-16\:\:square\:feet[/tex].
Keywords: rectangle, area
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