Respuesta :
Answer:
a) 2.592 m
b) 6.4 m
Explanation:
Given:
- The acceleration of blue ball a = 3.30 m/s^2
- The total track length s = 20.0 meters
- The initial velocity of red ball v_i = 5 m/s
Find:
a. How far is the second ball from the finish line at the instant the first ball reaches the line?
b. Assume the motion continues for both balls until the second ball reaches the finish line. What is the distance between the two balls at that time?
Solution:
- The amount of time taken by each ball to travel a distance of track s = 20 m is:
Blue ball: s = 0.5*a*t^2
20 = 0.5*3.3*t^2
t = sqrt ( 400 / 33 ) = 3.482 s
Red ball: s = v_o*t
20 = 5*t
t = 20 / 5 = 4 s
- Hence, blue ball reaches the distance of s = 20 m first @ t = 3.482s. The distance traveled by the Red ball in that time is:
Red ball @t=3.482
s = 5*(3.482) = 17.4078 m
- So at the end the distance between both balls is : 20 - 17.4078 = 2.592 m
- If the simulation continues, till Red ball reaches the finish line of track at s = 20 m in time t = 4s. The amount of distance traveled by the blue ball is:
s = 0.5*3.3*(4)^2
s = 26.4 m
- So at the end the distance between both balls is : 26.4 - 20 = 6.4 m
