Answer:
2080kJ
Explanation:
m(U4 - U1) = Q4 - W4
If P is less than 300kpa, then V = 0.4L
If P is greater than 300kpa, then V = 0.6L
If P is equal to 300kpa, then 0.4L < V < 0.6L
At 100kpa, vf = 0.001043m/kg and vg = 1.693m³/kg
Level 1
v1 = 0.001043 + 0.2 x 1.693 = 0.33964
m = V1/v1 ⇔ 0.4/0.33964
m = 1.178kg
u1 = 417.36 + 0.2 x 2088.7 = 835.1kJ/kg
Level 3
v3 = 0.6/1.178 = 0.5095 < vG = 0.6058 at P3 is equal to 300kpa
NOTE: Piston does reach upper stops to reach saturated vapor
Level 4
v4 = v3 = 0.5095m³/kg = vG at P4
P4 = 361kpa, u4 = 2550.0kJ/kg
1W4 = 1W2 + 2W3 + 3W4 = 0 + 2W3 + 0
1W4 = P2 (V3 - V2) = 300 x (0.6 - 0.4) = 60kJ
1Q4 = m(u4 -u1) + 1W4 = 1.178(2550.0 - 835.1) + 60 = 2080kJ