Respuesta :
Answer:
The final pressure in the two-flask assemblage is 1.8 atm
Explanation:
The given variables are
Flask 1 with gas A = 1.00 L at 5.00 atm
Flask 2 with gas B = 4.00 L at 1.00 atm
From the Daltons law of partial pressure which states that the total pressure of a given mixture of gases is equal to the sum of the partial pressures of the gases in the mixture
Ptotal = P₁ + P₂ + P₃
Final volume of both gases = 5.00 L
Boyle's law states that the pressure of a given mass of gas is inversely proportional to its volume
P₁·V₁ = P₂·V₂
Therefore their final pressure =
for gas A 1.00 L× 5.00 atm = 5.00 L × P₂
therefore P₂ = 1.00 atm
for gas B
1.00 atm × 4.00 L = P₂×5.00 L
Therefore P₂ = 4/5 atm
Total pressure P₂ for gas A + P₂ for gas B
1+4/5 atm or 1.8 atm
The final pressure in the two-flask assemblage is 1.8 atm
Determination of the final pressure for gas A
- Initial volume (V₁) = 1 L
- Initial pressure (P₁) = 5 atm
- Final volume (V₂) = 1 + 4 = 5 L
- Final pressure (P₂) =?
P₁V₁ = P₂V₂
5 × 1 = P₂ × 5
5 = P₂ × 5
Divide both side by 5
P₂ = 5 / 5
P₂ = 1 atm
Determination of the final pressure for gas B
- Initial volume (V₁) = 4 L
- Initial pressure (P₁) = 1 atm
- Final volume (V₂) = 1 + 4 = 5 L
- Final pressure (P₂) =?
P₁V₁ = P₂V₂
1 × 4 = P₂ × 5
4 = P₂ × 5
Divide both side by 5
P₂ = 4 / 5
P₂ = 0.8 atm
How to determine the final pressure in the two-flask assemblage
- Final pressure for gas A = 1 atm
- Final pressure for gas B = 0.8 atm
- Final pressure of mixture =?
Final pressure of mixture = Final pressure of A + Final pressure of B
Final pressure of mixture = 1 + 0.8
Final pressure of mixture = 1.8 atm
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