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29.Cu2S(g) + O2(g) → 2Cu + SO2(g)
What is the change in the oxidation number of copper in the reaction?​

Respuesta :

Answer:

In the reactant;   Cu2S  

2 Cu - 2(1) = 0

2 Cu = 2

Cu = 22

Cu = +1

In the product, Cu

Cu = O

The oxidation number of Cu in Cu2S and Cu respectively is +1 and 0 respectively

Explanation: