Respuesta :
[tex]\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &20300\\ r=rate\to 9.5\%\to \frac{9.5}{100}\dotfill &0.095\\ t=\textit{elapsed time}\dotfill &11\\ \end{cases} \\\\\\ A=20300(1-0.095)^{11}\implies A=20300(0.905)^{11}\implies \stackrel{\textit{rounded up}}{A=6770.65}[/tex]
